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2.Motion in Straight Line
medium
If the velocity of a particle is $(10 + 2t^2) m/s$, then the average acceleration of the particle between $2s$ and $5s$ is..........$m/s^2$
A
$2$
B
$4$
C
$12$
D
$14$
Solution
(d) Average acceleration $ = \frac{{{\rm{Change\, in\, velocity }}}}{{{\rm{Time\, taken }}}}$
$ = \frac{{{v_2} – {v_1}}}{{{t_2} – {t_1}}}$ $ = \frac{{\left[ {10 + 2{{(5)}^2}} \right] – \left[ {10 + 2{{(2)}^2}} \right]}}{3} = \frac{{60 – 18}}{3}$$ = 14\;m/{s^2}$.
Standard 11
Physics