A particle moves along a straight line. Its position at any instant is given by x=32 t-frac{8 t^3}{3

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2.Motion in Straight Line

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A particle moves along a straight line. Its position at any instant is given by $x=32 t-\frac{8 t^3}{3}$, where $x$ is in metre and $t$ is in second. Find the acceleration of the particle at the instant when particle is at rest $..........\,m / s ^2$

A$-16$

B$-32$

C$32$

D$16$

Solution

(b)
$v=\frac{d x}{d t}=32-8 t^2$
$v=0$ at $t=2 \,s \quad a=\frac{d v}{d t}=-16 t$
At $2\,s , \quad a=-32\,m / s ^2$

Standard 11

Physics

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