If the volume of a block of metal changes by | vedclass

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Question

The co-efficient of cubical expansion $y$ of the metal is given by

$Y=\frac{1}{V} 	imes \frac{\Delta V}{\Delta T}$

$Y=\frac{\Delta V}{V} 	imes

Vedclass · Accepted Answer

$2 	imes {10^{ - 5}}$

Vedclass · Answer

The co-efficient of cubical expansion $y$ of the metal is given by

$Y=\frac{1}{V} 	imes \frac{\Delta V}{\Delta T}$

$Y=\frac{\Delta V}{V} 	imes \frac{1}{\Delta T}$

Here, $\frac{\Delta V}{V}=\frac{0.12}{100}$

$\Delta T=20^{\circ} \mathrm{C}$

$Y=\frac{0.12}{100} 	imes \frac{1}{20}$

$Y=6 	imes\left.10^{-5}ight|^{0} C$

$	herefore$ Co-efficient of linear expansion of the metal is $:-$

$\alpha=\frac{Y}{3}=\frac{6.0 	imes 10^{-5}}{3}$

$\alpha=2.0 	imes\left.10^{-5}ight|^{0} C$

If the volume of a block of metal changes by $0.12\%$ when it is heated thrugh $20\,^oC$, the coefficient of linear expansion (in $^o{C^{ - 1}}$) of the metal is

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