Graph AB shown in figure is a plot of temperature of a body in degree Celsius and degree Fahrenheit.

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10-1.Thermometry, Thermal Expansion and Calorimetry

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The graph $AB$ shown in figure is a plot of temperature of a body in degree Celsius and degree Fahrenheit. Then

A

slope of line $AB$ is $9/5$

B

slope of line $AB$ is $5/9$

C

slope of line $AB$ is $1/9$

D

slope of line $AB$ is $3/9$

Solution

Relation between Celsius and Fahrenheit scale of

temperature is $\frac{\mathrm{C}}{5}=\frac{\mathrm{F}-32}{9} \Rightarrow \mathrm{C}=\frac{5}{9} \mathrm{F}-\frac{160}{9}$

Equating above equation with stanchard equation of line

$\mathrm{y}=\mathrm{mx}+\mathrm{c}$ we get slope of the line $\mathrm{AB}$ is $\mathrm{m}=\frac{5}{9}$

Standard 11

Physics

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