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6-2.Equilibrium-II (Ionic Equilibrium)
hard
If this is passed in solution of $0.1$ $M$ $Zn^{2+}$ and $0.01$ $M$ $Cu^{+}$ and concentration of ${S^{2 - }}$ made $8.1 \times {10^{ - 31}}$ $M$. Precipitation of $ZnS$ and $CuS$ will take place ? ${K_{sp}}$ of $\left( {ZnS} \right) = 3.0 \times {10^{ - 23}}$ and ${K_{sp}}$ of $\left( {CuS} \right) = 8.0 \times {10^{ - 34}}$
Option A
Option B
Option C
Option D
Solution
Precipitation of $CuS$ take place
Standard 11
Chemistry
