If time of flight of a projectile is 10 seconds. Range is 500 meters. maximum height attained by it

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3-2.Motion in Plane

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If time of flight of a projectile is $10$ seconds. Range is $500$ meters. The maximum height attained by it will be ......... $m$

A

$125 $

B

$50 $

C

$100 $

D

$150 $

Solution

(a)$T = \frac{{2u\sin \theta }}{g} = 10\sec \Rightarrow u\sin \theta = 50\;m/s$

$H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}} = \frac{{{{(u\sin \theta )}^2}}}{{2g}} = \frac{{50 \times 50}}{{2 \times 10}} = 125m$

Standard 11

Physics

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