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14.Probability
easy
If two dice are thrown simultaneously then probability that $1$ comes on first dice is
A
$\frac{1}{{36}}$
B
$\frac{5}{{36}}$
C
$\frac{1}{6}$
D
None of these
Solution
(c) Total number of ways $ = 6 \times 6 = 36$
Favourable number of ways $= \{ (1,1) (1,2) (1,3) (1,4) (1, 5) (1,6) \}$
$\therefore$ Required probability $= \frac{6}{{36}} = \frac{1}{6}.$
Standard 11
Mathematics
