- Home
- Standard 11
- Physics
10-1.Thermometry, Thermal Expansion and Calorimetry
normal
If two rods of length $L$ and $2L$ having coefficients of linear expansion $\alpha$ and $2\alpha$ respectively are connected so that total length becomes $3L$, the average coefficient of linear expansion of the composition rod equals:
A
$\frac{3}{2}\alpha $
B
$\frac{5}{2}\alpha $
C
$\frac{5}{3}\alpha $
D
none of these
Solution
Initial length of combination is $L+2 L=3 L$
Increment in first rod is $L \alpha \Delta t$
Increment in second rod is $(2 L)(2 \alpha) \Delta t=4 L \alpha \Delta t$
So increment in combination is sum of both so $5 L \alpha \Delta t$
Initial length of combination was $3 L$ so coefficient for combination is
$\frac {change}{initial \,length \times change\, in \,temperature}$
$=\frac{5 L \alpha \Delta t}{3 L \Delta t}=5 \alpha / 3$
Standard 11
Physics
Similar Questions
normal