A bar of iron is $10\, cm$ at $20°C$. At $19°C$ it will be ($\alpha$ of iron $= 11 \times 10^{-6}/°C$)
A bar of iron is $10\, cm$ at $20°C$. At $19°C$ it will be ($\alpha$ of iron $= 11 \times 10^{-6}/°C$)
- A
$11 \times 10^{-6} cm$ longer
- B
$11 \times 10^{-6} cm$ shorter
- C
$11 \times 10^{-5} cm$ shorter
- D
$11 \times 10^{-6} cm$ longer
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