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3 and 4 .Determinants and Matrices
medium
If value of a third order determinant is $11$, then the value of the square of the determinant formed by the cofactors will be
A
$11$
B
$121$
C
$1331$
D
$14641$
Solution
(d) ${\Delta ^c} = {\Delta ^{n – 1}} = {\Delta ^{3 – 1}} = {\Delta ^2} = {(11)^2} = 121$.
But we have to find the value of the square of the determinant, so required value is ${(121)^2} = 14641$.
Standard 12
Mathematics
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