Gujarati
3 and 4 .Determinants and Matrices
medium

If value of a third order determinant is $11$, then the value of the square of the determinant formed by the cofactors will be

A

$11$

B

$121$

C

$1331$

D

$14641$

Solution

(d) ${\Delta ^c} = {\Delta ^{n – 1}} = {\Delta ^{3 – 1}} = {\Delta ^2} = {(11)^2} = 121$.
But we have to find the value of the square of the determinant, so required value is ${(121)^2} = 14641$.

Standard 12
Mathematics

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