If $A = \left| {\,\begin{array}{*{20}{c}}5&6&3\\{ – 4}&3&2\\{ – 4}&{ – 7}&3\end{array}\,} \right|\,, $ then cofactors of the elements of $2^{nd}$ row are

Using Cofactors of elements of second row, evaluate $\Delta=\left|\begin{array}{lll}5 & 3 & 8 \\ 2 & 0 & 1 \\ 1 & 2 & 3\end{array}\right|$

If ${A_1},{B_1},{C_1}$…. are respectively the co-factors of the elements ${a_1},{b_1},{c_1}$,…… of the determinant $\Delta = \left| {\,\begin{array}{*{20}{c}}{{a_1}}&{{b_1}}&{{c_1}}\\{{a_2}}&{{b_2}}&{{c_2}}\\{{a_3}}&{{b_3}}&{{c_3}}\end{array}\,} \right|$, then $\left| {\begin{array}{*{20}{c}}{{B_2}}&{{C_2}}\\{{B_3}}&{{C_3}}\end{array}} \right| = $

In the determinant $\left| {\,\begin{array}{*{20}{c}}0&1&{ – 2}\\{ – 1}&0&3\\2&{ – 3}&0\end{array}\,} \right|$, the ratio of the co-factor to its minor of the element $-3$ is

Write Minors and Cofactors of the elements of following determinants: $\left|\begin{array}{ccc}1 & 0 & 4 \\ 3 & 5 & -1 \\ 0 & 1 & 2\end{array}\right|$