$\epsilon^{-1}=L^{3} M T^{-2} Q^{-2}, R=L^{2} M T^{-1} Q^{-2}, V=M L^{2} T^{-2} Q^{-1}, G=L^{3} M^{-1} T^{-2}$

As the angular displacement ( $\theta$ ) is dimensionless so

[displacement] $=\epsilon^{0} R^{0} G^{0} V^{0}$

Velocity, $[v]=L T^{-1}$

here $\epsilon^{-1} R^{-1} G^{0} V^{0}=L^{3} M T^{-2} Q^{-2} L^{-2} M^{-1} T^{1} Q^{2}=L T^{-1}=[v]$

dipole moment, $[p]=Q L$

here $\epsilon^{1} R^{0} G^{0} V^{1}=\left(L^{-3} M^{-1} T^{2} Q^{2}\right)\left(M L^{2} T^{-2} Q^{-1}\right)=Q L^{-1} \neq[p]$

force, $[f]=\epsilon^{-1} L^{-2} Q^{2}$

here $\epsilon^{1} R^{0} G^{0} V^{2}=\left(L^{-3} M^{-1} T^{2} Q^{2}\right)\left(M^{2} L^{4} T^{-4} Q^{-2}\right)=\left(L^{3} M T^{-2} Q^{-2}\right) L^{-2} Q^{2}=$

$\epsilon^{-1} L^{-2} Q^{2}=[f]$