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1.Units, Dimensions and Measurement
easy
Let us consider an equation
$\frac{1}{2} m v^{2}=m g h$
where $m$ is the mass of the body. velocity, $g$ is the acceleration do gravity and $h$ is the height. whether this equation is dimensionally correct.
Option A
Option B
Option C
Option D
Solution
Answer The dimensions of $LHS$ are
$[ M ]\left[ L T ^{-1}\right]^{2}=[ M ]\left[ L ^{2} T ^{-2}\right]$
$=\left[ M L ^{2} T ^{-2}\right]$
The dimensions of $RHS$ are
$[ M ]\left[ L T ^{-2}\right][ L ]=[ M ]\left[ L ^{2} T ^{-2}\right]$
$=\left[ M L ^{2} T ^{-2}\right]$
The dimensions of $LHS$ and $RHS$ are the same and hence the equation is dimensionally correct.
Standard 11
Physics
