In Delta ABC , m ∠ B =90, BC =3 and AC =5, then tan A =ldots ldots ldots ldots

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8. Introduction to Trigonometry

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In $\Delta ABC , m \angle B =90, BC =3$ and $AC =5,$ then $\tan A =\ldots \ldots \ldots \ldots$

A

$\frac{3}{4}$

B

$\frac{5}{3}$

C

$\frac{4}{5}$

D

$\frac{3}{2}$

Solution

In $\Delta ABC , \,m \angle B =90\,\, \,\,\therefore \overline{ AC }$ is a hypotenuse.

$BC =3$ and $AC =5$

$\therefore AB ^{2}= AC ^{2}- BC ^{2}=5^{2}-3^{2}=25-9=16=4^{2}$

$\therefore AB =4$

$\therefore \tan A =\frac{ BC }{ AB }=\frac{3}{4}$

Standard 10

Mathematics

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