In _{88}R{a^{226}} nucleus, there are

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13.Nuclei

easy

In $_{88}R{a^{226}}$ nucleus, there are

A

$138$ protons and $88$ neutrons

B

$138$ neutrons and $88$ protons

C

$226$ protons and $88$ electrons

D

$226$ neutrons and $138$ electrons

Solution

(b) $_z{X^A}{ = _{88}}R{a^{226}}$

Number of protons $= Z = 88$

Number of neutrons $ = A – Z = 226 – 88 = 138$.

Standard 12

Physics

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