In LiAlH₄, metal Al is present in

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p-Block Elements - I

easy

In $LiAlH_4,$ metal $Al$ is present in

A

anionic part

B

cationic part

C

in both anionic and cationic part

D

neither in cationic nor in anionic part

Solution

$\mathrm{LiAlH}_{4}$ is a reducing agent, composed of $\mathrm{Li}^{+}$ cation and $\mathrm{AlH}_{4}^{-}$ anion.

Therefore metal Al is present in anionic part.

Hence correct option is ( $\mathrm{A}$ ).

Standard 11

Chemistry

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