In a box there are 2 red, 3 black and 4 white | vedclass

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(c) Total number of ways in which $3$ balls can be drawn are ${}^9{C_3} = 84.$

Since the drawn balls can&rsquo;t be of red colour, as these are $2$

Vedclass · Accepted Answer

$\frac{5}{{84}}$

Vedclass · Answer

(c) Total number of ways in which $3$ balls can be drawn are ${}^9{C_3} = 84.$

Since the drawn balls can&rsquo;t be of red colour, as these are $2$ in numbers.

Therefore favourable number of ways $ = {}^3{C_3} + {}^4{C_3}.$

Hence the required probability $ = \frac{5}{{84}}.$

In a box there are $2$ red, $3$ black and $4$ white balls. Out of these three balls are drawn together. The probability of these being of same colour is

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