In a certain region uniform electric field E and magnetic field B are present in opposite direc

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8.Electromagnetic waves

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In a certain region uniform electric field $E$ and magnetic field $B$ are present in the opposite direction. At the instant $t = 0,$ a particle of mass $m$ carrying a charge $q$ is given velocity $v_o$ at an angle $\theta ,$ with the $y$ axis, in the $yz$ plane. The time after which the speed of the particle would be minimum is equal to

A

$\frac{{m{v_o}}}{{qE}}$

B

$\frac{{m{v_o}\sin \theta }}{{qE}}$

C

$\frac{{m{v_o}\cos \theta }}{{qE}}$

D

$\frac{{2\pi m}}{{qB}}$

Solution

Impulse of $'qE'$ will remove its momentum along $\mathrm{x}$

$\mathrm{q} \mathrm{E} \cdot \mathrm{t}=\mathrm{mv}_{0} \sin \theta$

Standard 12

Physics

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