Gujarati
Hindi
10-2.Transmission of Heat
normal

In a composite rod, when two rods of different lengths and of the same area are joined end to end. If $K$ is the coefficient of thermal conductivity of composite rod, then $\left( {\frac{{{\ell _1} + {\ell _2}}}{K}} \right)$ is equal to

A

$\frac{{{\ell _1}}}{{{K_1}}} - \frac{{{\ell _2}}}{{{K_2}}}$

B

$\frac{{{\ell _1}}}{{{K_2}}} - \frac{{{\ell _2}}}{{{K_1}}}$

C

$\frac{{{\ell _1}}}{{{K_1}}} + \frac{{{\ell _2}}}{{{K_2}}}$

D

$\frac{{{\ell _1}}}{{{K_2}}} + \frac{{{\ell _2}}}{{{K_1}}}$

Solution

$\mathrm{R}_{\mathrm{eq}^{-}}=\mathrm{R}_{1}+\mathrm{R}_{2}$

$\left(\frac{\ell_{1}+\ell_{2}}{\mathrm{K}_{\mathrm{eq}} \mathrm{A}}\right)=\frac{\ell_{1}}{\mathrm{K}_{1} \mathrm{A}}+\frac{\ell_{2}}{\mathrm{K}_{2} \mathrm{A}}$

$\frac{\ell_{1}+\ell_{2}}{\mathrm{K}}=\frac{\ell_{1}}{\mathrm{K}_{1}}+\frac{\ell_{2}}{\mathrm{K}_{2}}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.