In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at centre of surface ' S ' h

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1. Electric Charges and Fields

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In a cuboid of dimension $2 L \times 2 L \times L$, a charge $q$ is placed at the centre of the surface ' $S$ ' having area of $4 L ^2$. The flux through the opposite surface to ' $S$ ' is given by

A

$\frac{ q }{12 \varepsilon_0}$

B

$\frac{ q }{3 \varepsilon_0}$

C

$\frac{ q }{2 \varepsilon_0}$

D

$\frac{q}{6 \varepsilon_0}$

(JEE MAIN-2023)

Solution

$\phi=\frac{ Q / \varepsilon_0}{6}$

Flux passing through shaded face $=\frac{ q }{6 \varepsilon_0}$

Standard 12

Physics

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