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11.Thermodynamics
medium
In a cyclic process, a gas is taken from state $A$ to $B$ via path $-I$ as shown in the indicator diagram and taken back to state $A$ from state $B$ via path $-II$ . In the complete cycle

A
positive work is done on the gas
B
heat is given to gas
C
no work is done by the gas
D
nothing can be said about work as data is insufficient
Solution

As work done in state $(II)$ is more than in state $(I)$
Standard 11
Physics
Similar Questions
In Column $-I$ processes and in Column $-II$ formulas of work are given. Match them appropriately :
Column $-I$ | Column $-II$ |
$(a)$ Isothermal process | $(i)$ $W = \frac{{\mu R({T_1} – {T_2})}}{{\gamma – 1}}$ |
$(b)$ Adiabatic process | $(ii)$ $W = P\Delta V$ |
$(iii)$ $W = 2.303\,\mu RT\log \left( {\frac{{{V_2}}}{{{V_1}}}} \right)$ |
easy