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14.Probability
medium
In a horse race the odds in favour of three horses are $1:2 , 1:3$ and $1:4$. The probability that one of the horse will win the race is
A
$\frac{{37}}{{60}}$
B
$\frac{{47}}{{60}}$
C
$\frac{1}{4}$
D
$\frac{3}{4}$
Solution
(b) Probabilities of winning the race by three horses are $\frac{1}{3},\,\,\frac{1}{4}$ and $\frac{1}{5}.$
Hence required probability $ = \frac{1}{3} + \frac{1}{4} + \frac{1}{5} = \frac{{47}}{{60}}.$
Standard 11
Mathematics
Similar Questions
Fill in the blanks in following table :
$P(A)$ | $P(B)$ | $P(A \cap B)$ | $P (A \cup B)$ |
$\frac {1}{3}$ | $\frac {1}{5}$ | $\frac {1}{15}$ | …….. |
easy