In a radioactive sample there are 1.414 times | vedclass

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Question

$\mathrm{N}=\frac{\mathrm{N}_{0}}{2^{\mathrm{n}}}$

$\Rightarrow 10^{6}=\frac{1.414 	imes 10^{6}}{2^{\mathrm{n}}}$

$\Rightarrow 2^{n}=1.414$

Vedclass · Accepted Answer

$20$

Vedclass · Answer

$\mathrm{N}=\frac{\mathrm{N}_{0}}{2^{\mathrm{n}}}$

$\Rightarrow 10^{6}=\frac{1.414 	imes 10^{6}}{2^{\mathrm{n}}}$

$\Rightarrow 2^{n}=1.414$

$	herefore \quad n=1 / 2$

$	herefore \quad t = \frac{{{T_{1/2}}}}{2} \Rightarrow {T_{1/2}} = 20\,{m{mins}}$

In a radioactive sample there are $1.414 \times 10^6$ active nuclei. If they reduce to $10^6$ within $10\, minute$ then the half life of this sample will be ....... $min$

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