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13.Nuclei
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A radioactive sample is $\alpha$-emitter with half life $138.6$ days is observed by a student to have $2000$ disintegration/sec. The number of radioactive nuclei for given activity are
A
$3.45 × 10^{10}$
B
$1 ×10^{10}$
C
$3.45 × 10^{15}$
D
$2.75 × 10^{11}$
Solution
(a) Activity of substance that has $2000$ disintegration/sec
$ = \frac{{2000}}{{3.7 \times {{10}^{10}}}} = 0.054 \times {10^{ – 6}}ci = 0.054\,\mu ci$
The number of radioactive nuclei having activity $A$
$N = \frac{A}{\lambda } = \frac{{2000 \times {T_{1/2}}}}{{{{\log }_e}2}}$
$ = \frac{{2000 \times 138.6 \times 24 \times 3600}}{{0.693}} = 3.45 \times {10^{10}}$
Standard 12
Physics
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