In a simultaneous throw of three coins, probability of getting at least 2 tails

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14.Probability

easy

In a simultaneous throw of three coins, what is the probability of getting at least $2$ tails

A

$\frac{1}{8}$

B

$\frac{1}{4}$

C

$\frac{1}{2}$

D

None of these

Solution

(c) Total ways are $8$ and favourable ways are $4$

$S = \left\{ {HHH,\,HHT\,…….TTT} \right\}.$

Hence probability $ = \frac{4}{8} = \frac{1}{2}.$

Standard 11

Mathematics

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