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14.Probability
easy
Two dice are tossed. The probability that the total score is a prime number is
A
$\frac{1}{6}$
B
$\frac{5}{{12}}$
C
$\frac{1}{2}$
D
None of these
Solution
(b) Prime numbers are $\{ 2,\,3,\,5,\,7,\,11\} .$
Hence required probability
$ = \frac{{1 + 2 + 4 + 6 + 2}}{{36}} = \frac{{15}}{{36}} = \frac{5}{{12}}.$
Standard 11
Mathematics