In an LC circuit, capacitor has maximum charge q_0 . value of is {left. {frac{{di}}{{dt}}} right|_{m

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7.Alternating Current

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In an $LC$ circuit, the capacitor has maximum charge $q_0$. The value of is ${\left. {\frac{{di}}{{dt}}} \right|_{\max }}$

A

$\frac{{{q_0}}}{{LC}}$

B

$\frac{{{q_0}}}{{\sqrt {LC} }}$

C

$\frac{{{q_0}}}{{LC}} - 1$

D

none of these

Solution

$\left(V_{C}\right)_{\max }=\left(V_{L}\right)_{\max }$

$\frac{q_{0}}{C}=L\left(\frac{d I}{d t}\right)_{\max }$

$\therefore\left(\frac{d I}{d t}\right)_{\max }=\frac{q_{0}}{L C}$

Standard 12

Physics

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