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7.Alternating Current
easy
A $0.7$ henry inductor is connected across a $120\,V$ -$ 60 \,Hz$ $ac$ source. The current in the inductor will be very nearly
A
$4.55\, amp$
B
$0.355 \,amp$
C
$0.455\, amp$
D
$3.55\, amp$
Solution
(c) $i = \frac{V}{{{X_L}}} = \frac{{120}}{{2 \times 3.14 \times 60 \times 0.7}} = 0.455\,A$
Standard 12
Physics
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