Gujarati
7.Alternating Current
easy

A $0.7$ henry inductor is connected across a $120\,V$ -$ 60 \,Hz$ $ac$ source. The current in the inductor will be very nearly

A

$4.55\, amp$

B

$0.355 \,amp$

C

$0.455\, amp$

D

$3.55\, amp$

Solution

(c) $i = \frac{V}{{{X_L}}} = \frac{{120}}{{2 \times 3.14 \times 60 \times 0.7}} = 0.455\,A$

Standard 12
Physics

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