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11.Thermodynamics
medium
In an adiabatic change, the pressure $P$ and temperature $T$ of a monoatomic gas are related by the relation $P \propto {T^C}$, where $C$ equals
A
$5/3$
B
$2/5$
C
$3/5$
D
$5/2$
(AIIMS-2001) (AIPMT-1994) (AIIMS-2007)
Solution
(d) ${T^\gamma }{P^{1 – \gamma }}$= constant ==> $P \propto {T^{\frac{\gamma }{{\gamma – 1}}}}$
Comparing above equation with given equation
$P \propto {T^C}$ ==> $C = \frac{\gamma }{{\gamma – 1}} = \frac{{5/3}}{{5/3 – 1}} = \frac{5}{2}$
Standard 11
Physics
