In an adjoining figure three capacitors $C_1,\,C_2$ and $C_3$ are joined to a battery. The correct condition will be (Symbols have their usual meanings)
$Q_1 = Q_2 = Q_3$ and $V_1 = V_2 = V_3 = V$
$Q_1 = Q_2 + Q_3$ and $V = V_1 + V_2 + V_3$
$Q_1 = Q_2 + Q_3$ and $V = V_1 + V_2$
$Q_2 = Q_3$ and $V_2 = V_3$
The electric field $\vec E$ between two points is constant in both magnitude and direction. Consider a path of length d at an angle $\theta = 60^o$ with respect to field lines shown in figure. The potential difference between points $1$ and $2$ is
The electric potential $V$ at any point $(x,y,z)$ in space is given by equation $V = 4x^2\,volt$ where $x, y$ and $z$ are all in metre. The electric field at the point $(1\,m, 0, 2\,m)$ in $V/m$ is
$n$ small drops of same size are charged to $V$ $volts$ each. If they coalesce to form a signal large drop, then its potential will be
What is the equivalent capacitance of the system of capacitors between $A$ and $B$ :-
Electric field inside a uniformly charged sphere of radius $R,$ is ($r$ is distance from centre, $r < R$)