Three capacitors 1, 2 and 4,μ F are connected in series to a 10, volts source. charge on plates of

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1. Electric Charges and Fields

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Three capacitors $1, 2$ and $4\,\mu F$ are connected in series to a $10\, volts$ source. The charge on the plates of middle capacitor is

A

$7\,\mu C$

B

$\frac{{40}}{7}\,\mu C$

C

$\frac{{20}}{7}\,\mu C$

D

$\frac{{1}}{7}\,\mu C$

Solution

$\frac{1}{C}=1+\frac{1}{2}+\frac{1}{4}=\frac{7}{4} \Rightarrow C=\frac{4}{7}\, \mu F$

$\mathrm{Q}=\mathrm{CV}=\frac{4}{7} \times 10=\frac{40}{7}\, \mu \mathrm{C}$

Standard 12

Physics

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