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11.Dual Nature of Radiation and matter
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In an electron gun, the electrons are accelerated by the potential $V$. If e is the charge and $m$ is the mass of an electron, then the maximum velocity of these electrons will be
A
$\frac{{2eV}}{m}$
B
$\sqrt {\frac{{2eV}}{m}} $
C
$\sqrt {\frac{{2m}}{{eV}}} $
D
$\frac{{{V^2}}}{{2em}}$
Solution
(b) $eV = \frac{1}{2}m{v^2} $
$\Rightarrow {v^2} = \frac{{2eV}}{m} \Rightarrow v = \sqrt {\frac{{2eV}}{m}} $
Standard 12
Physics
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