An electron is accelerated through a potentia | vedclass

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Question

(a) $\frac{1}{2}m{v^2} = QV$

$ \Rightarrow v = \sqrt {\frac{{2QV}}{m}} = \sqrt {2\left( {\frac{e}{m}} ight)V} $

$ \Rightarrow v = \sqrt {2 	i

Vedclass · Accepted Answer

$8 	imes {10^6}\,m/s$

Vedclass · Answer

(a) $\frac{1}{2}m{v^2} = QV$

$ \Rightarrow v = \sqrt {\frac{{2QV}}{m}} = \sqrt {2\left( {\frac{e}{m}} ight)V} $

$ \Rightarrow v = \sqrt {2 	imes 1.6 	imes {{10}^{11}} 	imes 200} = 8 	imes {10^6}m/s$.

An electron is accelerated through a potential difference of $200$ volts. If $e/m$ for the electron be $1.6 \times {10^{11}}$ $coulomb/kg$ , the velocity acquired by the electron will be

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