In an experiment a sphere of aluminium of mass 0.20, kg is heated upto 150,^oC . Immediately, it is

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10-1.Thermometry, Thermal Expansion and Calorimetry

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In an experiment a sphere of aluminium of mass $0.20\, kg$ is heated upto $150\,^oC$. Immediately, it is put into water of volume $150\, cc$ at $27\,^oC$ kept in a calorimeter of water equivalent to $0.025\, kg$. Final temperature of the system is $40\,^oC$. The specific heat of aluminium is ............ $J/kg\,-\,^oC$ (take $4.2\, Joule= 1\, calorie$)

A

$378$

B

$315$

C

$476$

D

$434$

(JEE MAIN-2017)

Solution

According to principle of calorimetry,

${Q_{given}} = {Q_{used}}$

$0.2 \times S \times \left( {150 – 40} \right) = 150 \times 1 \times \left( {40 – 27} \right) + 25$

$ \times \left( {40 – 27} \right)$

$0.2 \times S \times 110 = 150 \times 13 + 25 \times 13$

Specificheat of aluminium

$S = \frac{{13 \times 25 \times 7}}{{0.2 \times 110}} = 434J/k{g^ \circ }C$

Standard 11

Physics

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