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2. Electric Potential and Capacitance
easy
In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius $0.53 \times {10^{ - 10}}\,m$. Then the electrical potential produced by the nucleus at the position of the electron is......$V$
A
$-13.6$
B
$-27.2$
C
$27.2$
D
$13.6$
Solution
(c) $V = 9 \times {10^9} \times \frac{Q}{r} = 9 \times {10^9} \times \frac{{( + 1.6 \times {{10}^{ – 19}})}}{{0.53 \times {{10}^{ – 10}}}}= 27.2\,V$
Standard 12
Physics