Gujarati
Hindi
7.Gravitation
hard

In both figures shown below a hole along the diameter of earth. In first, a particle is released from $A$ and it oscillated with time period $T_1$. In second figure, same particle is released from point $B$ and it oscillates with time period $T_2$ then [$O$ is centre of earth]

A

$T_1 > T_2$

B

$T_1 < T_2$

C

$T_1 = 2T_2$

D

$T_1 = T_2$

Solution

Time period of oscillation is independent of the distance of the point from the centre of

earth. In both cases $ \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{R}_{\mathrm{e}}}{\mathrm{g}}}$

Standard 11
Physics

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