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7.Gravitation
easy
The weight of a body at the surface of earth is $18\,N$. The weight of the body at an altitude of $3200\,km$ above the earth's surface is $........\,N$ (given, radius of earth $R _{ e }=6400\,km$ )
A
$9.8$
B
$4.9$
C
$19.6$
D
$8$
(JEE MAIN-2023)
Solution
Acceleration due to gravity at height $h$ $g ^{\prime}=\frac{ g }{\left[1+\frac{ h }{ R }\right]^2}$
So weight at given height
$mg ^{\prime}=\frac{ mg }{\left[1+\frac{ h }{ R }\right]^2}=\frac{18}{\left[1+\frac{1}{2}\right]^2}=8\,N$
Standard 11
Physics
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