7.Gravitation
easy

The weight of a body at the surface of earth is $18\,N$. The weight of the body at an altitude of $3200\,km$ above the earth's surface is $........\,N$ (given, radius of earth $R _{ e }=6400\,km$ )

A

$9.8$

B

$4.9$

C

$19.6$

D

$8$

(JEE MAIN-2023)

Solution

Acceleration due to gravity at height $h$ $g ^{\prime}=\frac{ g }{\left[1+\frac{ h }{ R }\right]^2}$

So weight at given height

$mg ^{\prime}=\frac{ mg }{\left[1+\frac{ h }{ R }\right]^2}=\frac{18}{\left[1+\frac{1}{2}\right]^2}=8\,N$

Standard 11
Physics

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