In certain years a sum of money is doubled itself at 6 frac{1}{4} % simple interest per annum, then

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6.Interest

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In certain years a sum of money is doubled itself at $6 \frac{1}{4} \%$ simple interest per annum, then the required time (In $years$) will be

A

$12.5$

B

$8$

C

$25$

D

$16$

Solution

(d) S.I. $=\frac{P N R}{100}$ Sum of money doubles itself.

$\not P=\frac{\not P \times N \times 6.25}{100} \quad \therefore S . I .=P$

$N=\frac{100}{6.25}$

$N=16$ years.

Standard 13

Quantitative Aptitude

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