In Milikan’s experiment, an oil drop having charge q gets stationary on applying a potential d

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11.Dual Nature of Radiation and matter

easy

In Milikan’s experiment, an oil drop having charge $q$ gets stationary on applying a potential difference $V$ in between two plates separated by a distance $‘d’$. The weight of the drop is

A

$qVd$

B

$q\frac{d}{V}$

C

$\frac{q}{{Vd}}$

D

$q\frac{V}{d}$

Solution

(d) $QE = mg$.

$ \Rightarrow mg = \frac{{QV}}{d}$

Standard 12

Physics

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