In Millikan’s oil drop experiment, an oil drop of mass $16 \times {10^{ - 6}}kg$ is balanced by an electric field of ${10^6}V/m.$ The charge in coulomb on the drop, assuming $g = 10\,m/{s^2}$ is

  • A

    $6.2 \times {10^{ - 11}}$

  • B

    $16 \times {10^{ - 9}}$

  • C

    $16 \times {10^{ - 11}}$

  • D

    $16 \times {10^{ - 13}}$

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