- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
easy
In Millikan's experiment, an oil drop having charge $q$ gets stationary on applying a potential difference $V$ in between two plates separated by a distance $d$. The weight of the drop is
A
$\frac{q}{{Vd}}$
B
$q\frac{d}{V}$
C
$q\,Vd$
D
$q\frac{V}{d}$
Solution
$W = qE = q\frac{V}{d}$
Standard 12
Physics