In Millikan's experiment, an oil drop having charge $q$ gets stationary on applying a potential difference $V$ in between two plates separated by a distance $d$. The weight of the drop is
In Millikan's experiment, an oil drop having charge $q$ gets stationary on applying a potential difference $V$ in between two plates separated by a distance $d$. The weight of the drop is
- A
$\frac{q}{{Vd}}$
- B
$q\frac{d}{V}$
- C
$q\,Vd$
- D
$q\frac{V}{d}$
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