In photoelectric effect, the K.E. of electrons emitted from the metal surface depends upon

  • A

    Intensity of light

  • B

    Frequency of incident light

  • C

    Velocity of incident light

  • D

    Both intensity and velocity of light

Similar Questions

Energy of photon whose frequency is ${10^{12}}MHz,$ will be

When wavelength of incident photon is decreased then

A photo sensitive material is at $9\,m$ to the left of the origin and the source of light is at $7\,m $ to the right of the origin along $x$ -axis. The photosensitive material and the source of light start from rest and move, respectively, with $8 \widehat i \, m / s$ and $4 \widehat i \, m / s$ . The ratio of intensities at $t = 0$ to $t = 3\,s$ as received by the photosensitive material is :-

Monochromatic light with a frequency well above the cutoff frequency is incident on the emitter in a photoelectric effect apparatus. The frequency of the light is then doubled while the intensity is kept constant. How does this affect the photoelectric current?

A convex lens of focal length $40 \mathrm{~cm}$ forms an image of an extended source of light on a photoelectric cell. A current I is produced. The lens is replaced by another convex lens having the same diameter but focal length $20 \mathrm{~cm}$. The photoelectric current now is:

  • [JEE MAIN 2024]