Gujarati
3.Current Electricity
easy

In the circuit shown $P \ne R$, the reading of the galvanometer is same with switch $S$ open or closed. Then

A

${I_R} = {I_G}$

B

${I_P} = {I_G}$

C

${I_Q} = {I_G}$

D

${I_Q} = {I_R}$

(IIT-1999)

Solution

(a) Reading of galvanometer remains same whether switch S is open or closed, hence no current will flow through the switch i.e. $R$ and $G$ will be in series and same current will flow through them. ${I_R} = {I_G}$.

Standard 12
Physics

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