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3.Current Electricity
easy
In the circuit shown $P \ne R$, the reading of the galvanometer is same with switch $S$ open or closed. Then

A
${I_R} = {I_G}$
B
${I_P} = {I_G}$
C
${I_Q} = {I_G}$
D
${I_Q} = {I_R}$
(IIT-1999)
Solution
(a) Reading of galvanometer remains same whether switch S is open or closed, hence no current will flow through the switch i.e. $R$ and $G$ will be in series and same current will flow through them. ${I_R} = {I_G}$.
Standard 12
Physics
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