- Home
- Standard 12
- Physics
3.Current Electricity
medium
A resistance wire connected in the left gap of a meter bridge balances a $10\, \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2 .$ If the length of the resistance wire is $1.5 m ,$ then the length of $1\, \Omega$ of the resistance wire is $....... \times 10^{-2}\;m$
A
$1.5$
B
$1.0$
C
$10$
D
$15$
(NEET-2020)
Solution
$\frac{ R }{10}=\frac{\ell_{1}}{\ell_{2}}$
$\frac{ R }{10}=\frac{3}{2}$
$R=15 \Omega$
Length of $15 \Omega$ resistance wire is $1.5 m$
length of $1 \Omega$ resistance wire $=\frac{1.5}{15}=0.1$
$=1.0 \times 10^{-1} m$
Standard 12
Physics
Similar Questions
In a meter bridge experiment, the circuit diagram and the corresponding observation table are shown in figure
| $Sl$. $No$. | $R\, (\Omega )$ | $l\, (cm)$ |
| $1$. | $1000$ | $60$ |
| $2$. | $100$ | $13$ |
| $3$. | $10$ | $1.5$ |
| $4$. | $1$ | $1.0$ |
Which of the readings is inconsistent ?
