Gujarati
Hindi
7.Binomial Theorem
normal

In the expansion of ${\left( {\frac{{x\,\, + \,\,1}}{{{x^{\frac{2}{3}}}\,\, - \,\,{x^{\frac{1}{3}}}\,\, + \,\,1}}\,\, - \,\,\frac{{x\,\, - \,\,1}}{{x\,\, - \,\,{x^{\frac{1}{2}}}}}} \right)^{10}}$, the term which does not contain $x$ is :

A

$^{10}C_0$

B

$^{10}C_7$

C

$^{10}C_4$

D

none

Solution

$\frac{{{{\left( {{x^{\frac{1}{3}}}} \right)}^3}\,\, + \,\,1}}{{{x^{\frac{2}{3}}}\,\, – \,\,{x^{\frac{1}{3}}}\,\, + \,\,1}} = x^{1/3} + 1 $

$\Rightarrow (x^{1/3} – x^{1/2})^{10}$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.