3-2.Motion in Plane
medium

In the figure, a ball of mass $m$ is tied with two strings of equal length as shown. If the rod is rotated with angular velocity $\omega$, then

A$T_1 > T_2$
B$T_2 > T_1$
C$T_1=T_2$
D$T_1=\frac{T_2}{6}$

Solution

(a)
For vertical equilibrium
$T_1 \cos \theta=m g+T_2 \cos \theta$
$T_1=\frac{m g}{\cos \theta}+T_2$
$\theta < 90^{\circ} \text { so } \cos \theta > 0$
$\Rightarrow T_1 > T_2$
Standard 11
Physics

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