In the figure a capacitor is filled with dielectric. The resultant capacitance is
$\frac{{2{\varepsilon _0}A}}{d}\left[ {\frac{1}{{{k_1}}} + \frac{1}{{{k_2}}} + \frac{1}{{{k_3}}}} \right]$
$\frac{{{\varepsilon _0}A}}{d}\left[ {\frac{1}{{{k_1}}} + \frac{1}{{{k_2}}} + \frac{1}{{{k_3}}}} \right]$
$\frac{{{2\varepsilon _0}A}}{d}\left[ {{k_1} + {k_2} + {k_3}} \right]$
$\frac{{A{\varepsilon _0}}}{d}\left( {\frac{{{k_1}{k_2}}}{{{k_1} + {k_2}}} + \frac{{{k_3}}}{2}} \right)$
Angle between equipotential surface and lines of force is.......$^o$
A negative charged particle is released from rest in a uniform electric field. The electric potential energy of charge
A hollow conducting sphere is placed in a electric field proudced by a point charge placed at $P$ as shown in figure. Let $V_A, V_B, V_C$ be the potentials at points $A, B$ and $C$ respectively. Then
In an adjoining figure three capacitors $C_1,\,C_2$ and $C_3$ are joined to a battery. The correct condition will be (Symbols have their usual meanings)
A parallel plate capacitor with air between the plates has a capacitance of $9\, pF$. The separation between its plates is $'d'$. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant $K_1=3$ and thickness $\frac{d}{3}$ while the other one has dielectric constant $K_2 = 6$ and thickness $\frac{2d}{3}$. Capacitance of the capacitor is now....$pF$