Gujarati
Hindi
1. Electric Charges and Fields
normal

In the figure a capacitor is filled with dielectric. The resultant capacitance is

A

$\frac{{2{\varepsilon _0}A}}{d}\left[ {\frac{1}{{{k_1}}} + \frac{1}{{{k_2}}} + \frac{1}{{{k_3}}}} \right]$

B

$\frac{{{\varepsilon _0}A}}{d}\left[ {\frac{1}{{{k_1}}} + \frac{1}{{{k_2}}} + \frac{1}{{{k_3}}}} \right]$

C

$\frac{{{2\varepsilon _0}A}}{d}\left[ {{k_1} + {k_2} + {k_3}} \right]$

D

$\frac{{A{\varepsilon _0}}}{d}\left( {\frac{{{k_1}{k_2}}}{{{k_1} + {k_2}}} + \frac{{{k_3}}}{2}} \right)$

Solution

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Standard 12
Physics

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