Side length of equilateral triangle is $d. P$ is mid of side then potential at point $P, V_P$ is
$\frac{Q}{{2\pi { \in _0}d}}\left[ {2 + \sqrt 3 } \right]$
$\frac{Q}{{2\pi { \in _0}d}}\left[ {2 + \frac{1}{{\sqrt 3 }}} \right]$
$\frac{Q}{{4\pi { \in _0}d}}\left[ {4 + \sqrt 3 } \right]$
Zero
A solid spherical conducting shell has inner radius a and outer radius $2a$. At the center of the shell a point charge $+Q$ is located . What must the charge of the shell be in order for the charge density on the inner and outer surfaces of the shell to be exactly equal?
A charg $Q$ is divided into two parts $q$ and $Q-q$ and separated by a distance $R$ . The force of repulsion between them will be maximum when
Charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively which are at distance $2\,L$ apart, $C$ is the midpoint between $A$ and $B$ . The work done in moving a charge $+ Q$ along the semicircle $CRD$ is
Two similar tiny balls of mass $m$, each carrying charge $q$ are hung from silk thread of length $l$ as shown in Fig. These are separated by a distance $x$ and angle $2 \theta \sim 10$. Then for equilibrium :-
Two conducting spheres of radii $r_1$ and $r_2$ have same electric fields near their surfaces. The ratio of their electric potentials is