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2. Electric Potential and Capacitance
easy
A proton is about $1840$ times heavier than an electron. When it is accelerated by a potential difference of $1\, kV$, its kinetic energy will be......$keV$
A
$1840$
B
$1/1840$
C
$1$
D
$920$
(AIIMS-2003)
Solution
(c) $KE = QV = e \times 10^3 \,V = 1\,KeV.$
Standard 12
Physics
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