2. Electric Potential and Capacitance
easy

A proton is about $1840$ times heavier than an electron. When it is accelerated by a potential difference of $1\, kV$, its kinetic energy will be......$keV$

A

$1840$

B

$1/1840$

C

$1$

D

$920$

(AIIMS-2003)

Solution

(c) $KE = QV = e \times 10^3 \,V = 1\,KeV.$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.