In the following state whether $A=B$ or not :
$A=\{a, b, c, d\} ; B=\{d, c, b, a\}$
In the following state whether $A=B$ or not :
$A=\{a, b, c, d\} ; B=\{d, c, b, a\}$
$A=\{a, b, c, d\} ; B=\{d, c, b, a\}$
The order in which the elements of a set are listed is not significant.
$\therefore A=B$
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